Question

5.8. A given load is driven by a 460 V four-pole 60 Hz 100 hp three-phase induction motor, data for which are as follows: R = R' = 0.042; X = X = 0.20 22 x = large; Tre = 0.07.c, N.m For a speed of 1775 rpm, perform a comprehensive analysis (find the slip, currents, powers, torques, efficiency, and pf).

Answer 1

Now, Torque developed - Rotor output ولا where we = 8 27T XNor f We = 21 x 1725 wo R 185.88 reade ), Rokor Rotor outputs Rotar input-Rotor copper less Where, Rotor inputs fin - stator lowss Rotor input = (20.632x103) 311 R input (70.532x103)2 34 3x8 g w l xaou Rotor input (20.532x103) -959.51 Rotor input = 69572.49 W Rotor input = 69.522K Rotar copper loss = stator bess=953.54 i Roton output = Rotor input - Rotor copper des Rotone output - 68572049 - 959.51 Rotor output = 68612.48 Watts Rotor output 68612.98 GO Now, I dev wee 185.88 I dev 369.13 Nm (Torque developed Ans

Given, torque loss dute to rotational loss, TR = 0.07 We As we calculate above Wp 185.88 rad ir The = 0,07*185.88 13.01 16 Nm RE Ans. load torque, Z, a Tyev che < = 369.13 - 13.0116 는 36 356.12 Nm Asus

Now, output power, Pout Zx WR fout 2 356,12% 185.88 Part 66195.28 Watts Pout = 66, 195 K Watts Ans,

Pout Now, efficiency can by calculate as, *100% Pin no 660 18 5 x 70² * 100% 70,532 X303 ne 0.1385*100%, 22 ESO n = 93.85% Ans