Question

The following three images accompany one another. The second image is another version of the first which we are using in the example. How does image 4 change the function of the circuit (an input, 'a', has been added that logically influences the next state bits)?? Fill out the truth table to show the change.

Note: Q2, Q1, and Q0 are LED outputs from left to right respectively. D2, D1, and D0 are switches from left to right respectively. 'a' is now an added input.

Consider the following sequential circuit, which has no external inputs. REG3 is a 3-bit register. REG3 DO 00 00 DI 01 Q1 XOR

D[2] DIUI D[O D Flip Flop Flip Flop sw_in on sw in sw in clock clock clock 0121 0111 Q[o]

Present State Q2 Q1 0 QO Next State D2 D1 0 DO 0 0 0 1 0 0 1 0 1 0 0 1 0 0 1 0 1 1 1 0 1 0 0 1 0 1 0 1 0 1 0 1 0 1 1 1 1 0 1

Circuit Change:

Q2 Q1 Q0 DO D1 CA D2 Reg3 debouncer

Input Present State Next State a Q2 Q1 Q0 D2 DI DO 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 1 1 0 0 0 0 0 1 0 0 1 0 0 1 0 1 1 1

0 0
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Answer #1

for given change circuit given question @ we can write functions of input Do=do; Di= d (40%) D=0, [408.) (400) - Here additioIn circuit changed question ,as per truth table output is not redirecting in to input side .

Input present values are already given for that output is filled up based on this expression for D2, D1, D0.

For input A=0 , output is next step of input.

For input A=1 , output is previous step of input.

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