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Two metals (Metal A and Metal Z) were compared to see which metal had a higher specific heat. A 50.0 gram sample of each meta

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Answer #1

For metal A

Heat absorbed by water = Heat released by metal

Mass of water x Cpw x temperature change = Mass of metal x Cpm x temperature change

90g x 4.184 J/g-°C x 3.4°C = 50g x Cpm x (100-28.4)°C

Cpm = 1,280.304/3,580

= 0.3576 J/g-°C

For metal Z

Heat absorbed by water = Heat released by metal

Mass of water x Cpw x temperature change = Mass of metal x Cpm x temperature change

90g x 4.184 J/g-°C x 3.1°C = 50g x Cpm x (100-28.1)°C

Cpm = 1,280.304/3,595

= 0.3561 J/g-°C

metal A has the higher specific heat

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