Question

You will be given 60 ul of LDH stock solution. You need to determine the protein concentration of this stock solution and the

B. Making the 250 ug/ml and 25ug/ml working solutions: Serially dilute the LDH stock with Tris buffer (150mm, pH 8.8) so you

my questions are the following:

A) what is the concentration of the stock solution of LDH?

B) Based upon Part B of the protocol, show your calculations to make the 250ug/ml LDH solution.

C) Based upon Part B of the protocol, show your calculations to make the 25ug/ml LDH solution.

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Answer #1

Answer A:

Conc. of diluted LDH = (1 x 0.046)/1.5 = 0.030 mg/ml

Conc. of LDH = 0.030 x 100 (Included conversion factor)

                       = 3 mg/ml

Answer B:

Stock conc. (M1) = 3 mg/ml = 3000 µg/ml

Final conc. (M2) = 250 µg/ml

Volume required for final solution (V2) = 600 µl

Volume of need from stock solution (V1) = ?

According to formula of M1V1 = M2V2

V1 = M2V2/M1

      = (250 x 600)/3000

     = 50 µl

To make a 250 µg/ml solution, we need to take 50 µl of stock solution (3 mg/ml) and 550 µl of Tris buffer.

Answer C:

Now, consider the 250 µg/ml solution as stock conc. and use same formula.

V1 = (25 x 500)/250

      = 50 µl

To make a 25 µg/ml solution, we need to take 50 µl of solution B (250 µg/ml) and 450 µl of Tris buffer.

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