my questions are the following:
A) what is the concentration of the stock solution of LDH?
B) Based upon Part B of the protocol, show your calculations to make the 250ug/ml LDH solution.
C) Based upon Part B of the protocol, show your calculations to make the 25ug/ml LDH solution.
Answer A:
Conc. of diluted LDH = (1 x 0.046)/1.5 = 0.030 mg/ml
Conc. of LDH = 0.030 x 100 (Included conversion factor)
= 3 mg/ml
Answer B:
Stock conc. (M1) = 3 mg/ml = 3000 µg/ml
Final conc. (M2) = 250 µg/ml
Volume required for final solution (V2) = 600 µl
Volume of need from stock solution (V1) = ?
According to formula of M1V1 = M2V2
V1 = M2V2/M1
= (250 x 600)/3000
= 50 µl
To make a 250 µg/ml solution, we need to take 50 µl of stock solution (3 mg/ml) and 550 µl of Tris buffer.
Answer C:
Now, consider the 250 µg/ml solution as stock conc. and use same formula.
V1 = (25 x 500)/250
= 50 µl
To make a 25 µg/ml solution, we need to take 50 µl of solution B (250 µg/ml) and 450 µl of Tris buffer.
my questions are the following: A) what is the concentration of the stock solution of LDH?...
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