Question

Using the convolution property of Fourier Transform to find the following convolution: sinc(t) * sinc(40) [Hint: sinc(t) rect(w/2)] F TT sinc (4t) TE z sinc (26) TE 2 sinc(t) TT sinc (t) sinc(2t) Question 6 (10 points) Determine poles and zeros of transfer function H(s) 2(3-3) +58 +6 Zero: -3; Poles: -2 and -3 Zero: 3; Poles: -2 and -3 Zero: 2; Poles: -2 and 3 Zero: 0; Poles: 2 and -3

need help with these two. thank you!

Answer 1

Sinct sinat F.T Sinat Tot Sinnt F. 11 Sincat din ant ant at sinant ST Linant : 4 nt 411 het, 91 (t) X2lt) Sinet) - Sineft) ytt) X,(t) * 7214) Xi (W) X 2 (W) :-Y(W) Xilw) = X21W) - 4T

14 X, (W) X21W) Y1W) 7 -T YA + Sinnt it 1 Sintt . Ytt) = y It) Linct - Question 6 H(s) = 2(5-3) 3+55+6 215-3) HIS) (3+2) (5+3 Zeroes Roots of the numerd for of HIS) poles = Roots of the denominator of t15) (5-3) = 0 5 = 3 Zero: 3

(5+2) (5+3) S-3 S = -2 ana Poles are present at s=-2 and 5=-3 Zero: 39 poles: - 2 and - 3