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(1 point) In an LR circuit, L = 180 mH and R= 25 12. The switch is closed at t = 0. a) How long does it take to rise to 40% o

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(a) It will take 3.672 mS to rise to 40% of its final value.

(b) Final current is attained 99.32% of the final value in 5 time constants.

The circuit is a LR circuit, Lets take it! solution a series L-R circuit, where L = 180 mH & R = 252 switch is being closed aTake laplace transform Ži(s) R + L S ics) i (5o = V SCRALS) ri icso = VIL SCS+RL After partial fraction we get iles NIR VIR S(9) we have to find out the time at which current reaches 40% of its final value from equation ori 0.4 y = (1-éct) 0.4=1-ertso it will take 3.672 ms to rise to you. of its final value. 16) we know that the time constant of L-R circuit is: e = he soso 50 iz ucl-ee iz ž (1-25) oy or i = (0.9932) GiD We know = I is final value of current from equation 1 it can be seen that

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