Question

2. In the figure, block 1 with mass m = 0.300 kg and block 2 with mass m2 0.600 kg are connected by a massless string over a pulley with radius R 0.150 m and mass M = 0.400 kg. The blocks are accelerating at 3.00 m/s in the direction shown. Assuming the pulley rolls without slipping against the string, calculate: (a) the moment of inertia, 1, of the pulley, and (b) the tensions on either side of the pulley. my Ap - 0= P.-P. and p. - P. Ver ro 8,-++ --+20,-) K refsin - F MEME El.-M. Στο Ια AXB-(1,8 - 4B, )i+(4.B. -4,8) (48-4B.) C-4 sino -lo constant or - 7-21 y(x:1) = A sin(kx - ox) and var *(1) - Acos(ok *2.400()(---) ---I--, -2.2,.. s'Acos(er) y (24) T2 V

Answer 1

(a) Moment of inertia of pulley = 1/2 *M*R*R

M is the Mass of the pulley

R is the radius of pulley

= 0.5 * 0.4 * 0.15 * 0.15 = 0.0045  kilogram-metre square.

(b) The tension on an object is equal to the mass of the object x gravitational force plus/minus the mass x acceleration.

here ; since the body is accelerating upwards the sign of acceleration is negative

tension on m1 = (0.3 * 10 ) - 3 = 0 N

tension on m2 = (0.6 * 10) - 3 = 3 N

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