Question

a gas occupies a volume of 300cm^3 at the pressure of 103,97kpa and at the temperature of 47°c. what volume would the gas occupy at standard condition

Answer 1

Answer-

Initial volume of the gas(V₁) = 300 cm³

Initial pressure of the gas(p₁) = 103,97 kpa

Initial temperature of the gas(T₁) = 47°C = 273.15 + 47 =  320.15 K

At standard condition-

Pressure (P₂) = 101.3kPa

Temperatue = 273.15 K

Let volume at the standard condition = V₂

Now by ideal gas law-

P₁ V₁ / T₁ = P₂ V₂ / T₂

Put all the know values in the above equation-

103,97 kpa x 300 cm³  / 320.15 K = 101.3kPa x V₂ / 273.15 K

$\Rightarrow$

V₂ = (103,97 kpa x 300 cm³  x 273.15 K) / (320.15 K x 101.3kPa)

V₂ = 26270.45 cm³