Question

Two marksmen shoot at a target simultaneously. Shooter A is known to have a 70% chance of hitting the target on any attempt. Person B has 40% accuracy. After the target is hit for the first time, it is revealed that A shot 5 shots while B shot 12. What is the probability that it was A who hit the target? What is the probability that person B hit the target? (Assume that accuracy of the shots remain the same and are independent of other shots by either person.)

Expert comment:

• Here, it should be specified whether A or B will stop shooting as soon as, the bird is shot or they will continue until fifth shots.it should be specified whether one shot is sufficient for the bird or not

There is no bird mentioned. A and B shoot the targets, A shoots 5 times, B shoots 12.

Answer 1

Ans! - If A has the target that means a pst the target of sth shot Alor de omnissed on fost four where as B Owust have omissed call the 12 shots PLAnitting I Target wit) (0.35%0.7) 10.60)'? (0,39420.7) 2016092 +0,39510,6)'(0,4) 11 0.77778 P (Britting Target nit) (0.315x0.63" 2014) 10.394207) (0,672+10,39(0.6)'0.41 02222 CS Scanned with CamScanner