Question

2. Three weapons systems are shooting at the same target. From a design standpoint, each weapon has an equally likely chance to hitting the target. However in practice it has been observed that the precision of these weapons systems is not the same; that is, the first weapon usually hits the target 9 out of 12 shots, the second hits 8 out of 12, and the third hits 7 out of 12 shots. We observed that the target has been hit and we are interested in finding the probability that the shot was fired by the second weapon system al- b)-C-d-

Answer 1

A option

1/3

So,

P(second) = (8/12)/(9/12 + 8/12 + 7/12)

So,P = 1/3

Or

P = 0.33

Thus,

A option