Question

Question 1

Explain with the help of appropriate schematic diagrams and examples the importance of power factor correction with reference to energy use.

Question 2

What are the different energy use in a classroom?

How can the energy use be reduced? Use appropriate drawings if needed.

Answer 1

Power factor Coxsechoma Power factor u ratis between real system. power and apparent powel in -) A A The closes the voltage and current are in phase then the powes factor will be neaus to le because it curent and woltage are in phone the real and apparent will be equal. powes factor consection ìs nothing hut converting the circuit where the voltage and current au not in phare to where the voltage and current are in phone to each other. if they are perfectly in share then the power factor is 1 Actually there two parts to power factor I - Displacement power factor due to reachine loads. 2- distortion factor due to haimonies. Why power factor impoovement (correctin) important?. iets consides a system au 1004 at 480Y their system u rated at usox100 =48KVA ·

40 kw apparent power 0.95 MSOV P- 40kw ef=0.95 42. KVA tre can see apparent power ů leu than 48 KVA 42. IKVÁ 4%OV: lets consides system - 2 no power factor correction USU V10 P-40kW pt=0.84 SUOKW 50 KVA (This exceeds the rated ie 48 kVA) So this ù not safe. T = 50KVA 480Y I. = 1044 we can see So, ite we collect power factor then the apparent powes under the rated requirement Bauce powrfactor correchòn ù done by adding reactive load (capacitor) to counteract the reactive load in the circuit. ♡ 10 kW 9 KVAR 1 10²t qe 13.45 kVA

10 power factor 2015 Now if we introduce a capacitor with same akunk. V 10 XL 4 kune. AKVAR S= Tio't (9-9) Pf = 1%0 Now let us calculate the value of capacitor. uso v 332 60H 10.6MH <= 2xy + bx (0 % =412 he = 3tju = 5251112² Ip = 96A L-5113² S = (uso (96) SEVI 2460&KVA : P = (96) *3 =27.65KW. PRIR. Pf = P 3 27.65 20.6. 4608 reactive power of inductor Se = I xe = (26) * 4 = 36, S64 VAR Now we need the Capacitor with 8c . 36,564 VAR

V Xc Cuso) 36,864 VAR - Xe = сос whe 27X 60 X 6.25 C=424.4uF power i mos Pincreases. As the energy So if we place Capacitor Cathen the power factor will be equal to l. In this the real if the power factor a peoportonal to real powes So, enway increases if we inceare power factor.