1. A 10.0 mL vinegar sample was completely neutralized by 22.5 mL 0.20 M NaOH solution....
1. A 10.0 mL vinegar sample was completely neutralized by 22.5 mL 0.20 M NaOH solution.
A. Calculate molarity of the vinegar?
B. and % of Acetic acid in vinegar?
Homework Answers
Given data,
Volume of vinegar = 10.0 mL
Volume of NaOH = 22.5 mL
M1 x V1 = M2 x V2
M1 x 10 = 22.5 x 0.2
M1 = ( 22.5 x 0.2 ) / 10
= 0.45M
weight of acetic acid in a liter of solution = molartiy x molar mass
= 0.45 x 60g/mol
= 27 g /L
Thus % by weight of acetic acid in solution = 2.7%
Add Answer to:
1. A 10.0 mL vinegar sample was completely neutralized by 22.5
mL 0.20 M NaOH solution....
A titration of vinegar with a solution of NaOH was performed. If 3.35 mL of vinegar...
A titration of vinegar with a solution of NaOH was performed. If 3.35 mL of vinegar needs 45.0 mL of 0.135 M NaOH to reach the equivalence point in a titration CH3COOH(aq)+NaOH(aq)→H2O(l)+NaC2H3O2(aq) Part A: Calculate the mass of acetic acid present in the vinegar sample? Part B: How many grams of acetic acid are in each mL of vinegar? Part C:How many grams of acetic acid would be in a 1.60 qt sample of this vinegar? Part D: How many...
20. A 0.20 M NaOH Intention was used to literate the acetic acid in 10.0 mL...
20. A 0.20 M NaOH Intention was used to literate the acetic acid in 10.0 mL of an unknown Salesian The total haline of NaOH alertian used Completely neutralize the acesic alld in the solution was up to Calcubre the maksity of acetic acid in the linkown Soladian. 30.20 mL
4. Vinegar is a solution of acetic acid. Acetic acid has a 1:1 ratio when reacted...
4. Vinegar is a solution of acetic acid. Acetic acid has a 1:1 ratio when reacted with NaOH. a. Suppose that the molarity of acetic acid in vinegar is 0.5 M, how many grams of acetic acid are present in the 5 ml of vinegar solution used in the titration? (molar mass of acetic acid = 60 g/mol). b. If vinegar has a density of 1.01 g/mol. Calculate the % of acetic acid in vinegar by mass. 5. 50 ml...
please show all work. thank you A 10. equivalence point. L sample of vinegar, an aqueous solution of acetic acid (HC2H02), is titrated with 0.5003 M NaOH, and 15.00 mL is required to reach the a....
please show all work. thank you
A 10. equivalence point. L sample of vinegar, an aqueous solution of acetic acid (HC2H02), is titrated with 0.5003 M NaOH, and 15.00 mL is required to reach the a. What is the molarity of the acetic acid? b. If the density of the vinegar is 1.006 g/cm3, what is the mass percent of acetic acid in the vinegar?
A 10. equivalence point. L sample of vinegar, an aqueous solution of acetic acid (HC2H02),...
3. Record the volumes of NaOH solution in the burets shown below: 4. If a 10.0...
3. Record the volumes of NaOH solution in the burets shown below: 4. If a 10.0 mL sample of vinegar is titrated with 24.30 mL of 0.231 MN pink endpoint. Calculate the molarity of acetic acid in the vinegar, and the mass percent of acetic acid in the vinegar, assuming the vinegar solution has a density of 1.01 g/mL. Show all work.
5. Acetic acid (HC,H,Os) is an important component of vinegar. A 10.00-ml sample of vinegar is...
5. Acetic acid (HC,H,Os) is an important component of vinegar. A 10.00-ml sample of vinegar is titrated with 0.5052 M NaOH, and 16.88 mL are required to neutralize the acetic acid that is present a. Write a balanced equation for this neutralization reaction. b. What is the molarity of the acetic acid in this vinegar? c. If the density of the vinegar is 1.006 g/mL, what is the mass percent of acetic acid in the vinegar? 6. How many milliliters...
i need all answers Data Table 1: Titration of Vinegar with Sodium Hydroxide Vinegar Sample 1...
i
need all answers
Data Table 1: Titration of Vinegar with Sodium Hydroxide Vinegar Sample 1 Vinegar Sample 2 Vinegar Sample 3 Mass of Vinegar (6) Volume of Vinegar (ml) Density - 1.005 g/ml Initial NaOH volume in syringe (ml) Final NaOH volume in syringe (ml) Volume of NaOH delivered (mL) Volume of NaOH delivered (L) Molarity of NaOH Moles of NaOH delivered Reaction of NaOH with Acetic Acid Moles of Acetic Acid in vinegar sample Molar mass of Acetic...
acetic acid is an important ingredient of vinegar. a sample of 50.0 ml of a commercial...
acetic acid is an important ingredient of vinegar. a sample of 50.0 ml of a commercial vinegar is titrated against a 1.00 M NaOH solution. What is the molarity of acetic acid present in the vinegar if 5.75 ml of the base are needed for the titration?
How many mL of 1.000M NaOH solution would it take to neutralize 10.0mL of vinegar that...
How many mL of 1.000M NaOH solution would it take to neutralize 10.0mL of vinegar that contained 0.500M acetic acid? 5.50mL 4.50mL 5.40mL 5.00mL D Question 4 2 pts If 20.00 mL of a 0.1000M solution of NaOH is required to neutralize 10.00mL of vinegar, then the molarity of the acetic acid is 0.2500M 0.2000 M 0.5000 M Question 1 2 pts There is a 3:1 ratio between NaOH and acetic acid in the balanced chemical equation for this lab....
1. Volume of Vinegar used in each trial = 5.00 mL 2. Molarity of NaOH used...
1. Volume of Vinegar used in each trial = 5.00 mL 2. Molarity of NaOH used in each trial = 0.20M 3. Volume of NaOH used in trail#1 (Final – Initial buret reading) = __17.80______ mL 4. Volume of NaOH used in trail#2 (Final – Initial buret reading) = ___18.20_____ mL 5. Average Volume of NaOH used = (#3 + #4) / 2 = ___18______ mL 6. Calculate Molarity of Acetic acid in vinegar = _________ M ?????? (molarity of...
20. A 0.20 M NaOH Intention was used to literate the acetic acid in 10.0 mL of an unknown Salesian The total haline of NaOH alertian used Completely neutralize the acesic alld in the solution was up to Calcubre the maksity of acetic acid in the linkown Soladian. 30.20 mL
4. Vinegar is a solution of acetic acid. Acetic acid has a 1:1 ratio when reacted with NaOH. a. Suppose that the molarity of acetic acid in vinegar is 0.5 M, how many grams of acetic acid are present in the 5 ml of vinegar solution used in the titration? (molar mass of acetic acid = 60 g/mol). b. If vinegar has a density of 1.01 g/mol. Calculate the % of acetic acid in vinegar by mass. 5. 50 ml...
please show all work. thank you
A 10. equivalence point. L sample of vinegar, an aqueous solution of acetic acid (HC2H02), is titrated with 0.5003 M NaOH, and 15.00 mL is required to reach the a. What is the molarity of the acetic acid? b. If the density of the vinegar is 1.006 g/cm3, what is the mass percent of acetic acid in the vinegar?
A 10. equivalence point. L sample of vinegar, an aqueous solution of acetic acid (HC2H02),...
3. Record the volumes of NaOH solution in the burets shown below: 4. If a 10.0 mL sample of vinegar is titrated with 24.30 mL of 0.231 MN pink endpoint. Calculate the molarity of acetic acid in the vinegar, and the mass percent of acetic acid in the vinegar, assuming the vinegar solution has a density of 1.01 g/mL. Show all work.
5. Acetic acid (HC,H,Os) is an important component of vinegar. A 10.00-ml sample of vinegar is titrated with 0.5052 M NaOH, and 16.88 mL are required to neutralize the acetic acid that is present a. Write a balanced equation for this neutralization reaction. b. What is the molarity of the acetic acid in this vinegar? c. If the density of the vinegar is 1.006 g/mL, what is the mass percent of acetic acid in the vinegar? 6. How many milliliters...
i
need all answers
Data Table 1: Titration of Vinegar with Sodium Hydroxide Vinegar Sample 1 Vinegar Sample 2 Vinegar Sample 3 Mass of Vinegar (6) Volume of Vinegar (ml) Density - 1.005 g/ml Initial NaOH volume in syringe (ml) Final NaOH volume in syringe (ml) Volume of NaOH delivered (mL) Volume of NaOH delivered (L) Molarity of NaOH Moles of NaOH delivered Reaction of NaOH with Acetic Acid Moles of Acetic Acid in vinegar sample Molar mass of Acetic...
How many mL of 1.000M NaOH solution would it take to neutralize 10.0mL of vinegar that contained 0.500M acetic acid? 5.50mL 4.50mL 5.40mL 5.00mL D Question 4 2 pts If 20.00 mL of a 0.1000M solution of NaOH is required to neutralize 10.00mL of vinegar, then the molarity of the acetic acid is 0.2500M 0.2000 M 0.5000 M Question 1 2 pts There is a 3:1 ratio between NaOH and acetic acid in the balanced chemical equation for this lab....
Most questions answered within 3 hours.
-
ECO
2013 &
asked 1 minute ago -
Insight refers to:
a.
Adaptive decision-making
b.
Credibility and trustworthness
c.
Understanding of one's problems
d....
asked 7 minutes ago -
Explain the differences between rights and permissions within
Windows. Define the principle of least privilege and...
asked 14 minutes ago -
A solid, frictionless cylindrical reel of mass M=5.00kg and
radius R=0.55m is used to draw water...
asked 17 minutes ago -
how do radio waves get emitted from Jupiter?
- do they come from radiation from planet...
asked 17 minutes ago -
The test statistic used in the F test for the equality of two
variances is calculated...
asked 29 minutes ago -
How does neutralisation of IL-6 trans-signaling affect the
autoimmune disease and inflammation? What if the trans-signaling...
asked 19 minutes ago -
f an allele is 'fixed' in a population, what is its
frequency?
0.50
0.75
0.25
0...
asked 33 minutes ago -
Do we have a duty of national loyalty in business? What is the
major argument in...
asked 34 minutes ago -
compare the international treatment of segment reporting to the
us gaap treatment
asked 30 minutes ago -
A statistics student finds herself struggling with a newspaper
article stating that only eighteen percent of...
asked 1 hour ago -
People with beriberi, a disease caused by a thiamin deficiency,
have elevated levels of blood pyruvate...
asked 50 minutes ago