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Score: 0 of 3 pts 33 of 37 (30 complete) 13.6.33 Consider the following equation of a quadric surface. x2 2 2 256 256 256 a.
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+ x2 + y2 - 22 = 256 (a) with x-axis: y=0,2=0=x = 256x=-16,16 the x-intercepts are located at x=16, x=-16 with y-axis x=0,2 =

50 -50 50 у о 50 50 -50

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