As we know that first order process:
ln(C/Co) = -kt
here C = The concentration of the remaining at time t;
Co =The initial concentration;
k = THe rate constant
As from the question it is given 60% decomposes therefore 40% remains
=>C/Co * 100% = 40% => C/Co = 0.40
ln(0.40) = -k * 60 =>-0.91 = -k*60
=>rate constant k = 0.0152 min-1
and the Half-life = ln(2)/k
= 0.6931/0.0152
= 45.59 ≈ 45 minutes
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