Question

0.JJJ U.JUJU U.12 WORKED Example 28 (11 A box contains 6 red marbles and 4 blue marbles. One marble is randomly drawn. colour noted and the marble put back in the box. This procedure is done two more time Represent the information as a tree diagram and calculate the probability of getting: a three red marbles b two red marbles and one blue marble in any order c three red marbles or three blue marbles. 58998092 'n Squeeze

Answer 1

From a red marble = 6 lo given, probability of getting Poobability of getting blue marble = 4 ami Tree diagram 2nd ist draw draw 3rd draw outcome & Probabilit 63 R 103 R B R 4/10 6/10 4/10 6/10 4/10 6/10 4/10 R ole B. 13 PCR,RR) a PCR,R,13) = 66**9/13) PCR,13,R) - (6441103) PCR,B,B). (4+1/103) PCB,R,R) = 624/10) P(BRB) = 4²x6/103 P(B, B,R) = 4²x6/103 B,3) 6/10 R R B 4 B 4/10 6/10 R To B 4/10 3 u²/10 B P(B, Total Sum of probabilities 6'+ 3(6x4) + 3(4’x6) +47 Too - 31. 1000 1000 ire, red balls P(R,R, R) ^ a) Three 3 6 10.216 & 1 Blue. b) Two red ie, pler, B) + P(R2,8,12), + PCB, R,R] L ㄴ OR OR 6 x 6 x 4 6 x 4 x 6 4 x 6 x 6 103 103 lo3 10.432 c) Three Red con Three blue PCR, R, R) + PCB,BB) 6 X 6 X6 - 4x4x4 103 103 280 = O. 28 1000

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