Question

for the circuit below: a. Circuit Impedance in polar and rectangular form. b. Is the circuit more inductive or more capacitive? c. Draw the impedance phasor diagram. d. The net reactance that will make the impedance magnitude equal to 100 ohms. e. Itot, VR, VL, and VC in polar form. f. Draw the voltage phasor diagram. 47 2 80 2 35 22 4_ov frequency is 5KHz:

Answer 1

4752 352 sol Given circuit gor m2 L th R 420 V capacitive impedance = -j Xc -j 35 r. Anduetive impedance - jxL =json connection Hence circuit impedanee - R+j x-jxc ( For series = 47+ jso - j35 of R,L,CI = 47+ 345 In folar form ; circuit impedance, 45 Z = 145*747<tan" ( 65.07 243.75 Z In reetangular form, circuit impedance (4 7+345) z = Am 6 Circuit is more inductive as value of greater than Enductive reactance, X, is capacitance react ande, Xe as XL = 60, Xc = 352.

c) Impedance Phasor diagram Z= 65.07243-75° AjXL 450k. -Xc). Z (Circuit impedance) RtjXL-Xe). * R=47 | 43.75° VjXc. d) for impedance magnitude to be loos VR+X-X.) i.e. Z=100 100 - 547²+ (Xnet)? → 100²_47² = (Xnet)² Xnet = too²_472 Xnet a 88.27 r. 100 s impedance : Net Reactance to be used for to [88.27 2 (approx) Aug is equal

le) division 47 jso -75 Applying voltage 47 ) (46) m M VR 4 40° 47 44 20 ) 65007243.750 VRE 2.89 2-43.75 V Ang V = 380 Z -) (4200) - 80290° 1440) 65.07 243.75° V = 4.92 % 46-25° V Aug Vc = ( ) (46) 35 2-90 65-07243-75% (4209) Ve 2015 Z-133.75° v Any

Voltage phasor diagram V = 4.92 246-25 VEVO 46.25 (Reference Phaser +43-75 ts=4 loov. 133.15 VR= 2.89 -43.75° V. Vs = sousce voltage Is = JR + - li Vc = 2.15 -133.759