After designig primers to target a gene of interest, you recieve 33.4 nmoles of a forward...
Homework Answers
Molarity or molar concentration is the amount of solute (measured as mole) per unit volume of solution ( measured in litres).
Hence, Molarity = no. of moles of solute ÷ volume of solution in litre.
In the question, we have 33.4 n moles of forward primer. With this amount of the primer, to obtain a 100uM solution, we need 0.000334L of water (334 uL of water).
Since, Volume of solution(L) = no.of moles ÷ molarity
But, instead a solution of 1mM was obtained. Volume of water in 1mM solution of 33.4nmole primer is 0.0000334L (that is 33.4 uL)
Hence, the volume of water required to convert a 1nM solution of 33.4n moles of a primer into a 100uM solution is the difference in the calculated water requirement for 100uM solution and the actual water content in1mM solution.
That is, amount of water required = 334uL -33.4uL = 300.6uL
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After designig primers to target a gene of interest, you recieve
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a template is in a 50 ng/ul solution. The protocol is as
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VOLUME TO ADD FINAL CONCENTRATION 0.5 UM 0.5 M REAGENT 10 PM Forward Primer 10 PM Reverse Primer Thermoestable pol Master mix 2x Template DNA water 1x 100 ng.. Total volume 25 ul Information about the primers: Forward primer: 29.3 nmoles - 220 ug...
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