4 ) Given figures in the question are:
Concentration of original solution: 50Mm
Concentration of diluted solution: 0.1 Mm
Volume of diluted solution = 50 ml
M1V1 = M2V2
M1 = Concentration of the first solution
V1 = Volume of the first solution
M2 = Concentration of second solution
V2 = Volume of the second solution
50 * V1 = 0.1 * 50
V1 = (M2 * V2) / M1
V1 (Volume of original solution) = (0.1 * 50 ) / 50
= 0.1 ml
Volume of original solution is 0.1 ml
5) The amount of water you need to make 50 ml solution
= V2 (Volume o diluted solution) - V1 (Volume of original solution)
= 50 ml - 0.1 ml = 49.9 ml
49.9 ml water is needed
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