Question

You require a solution containing 127 mM of sodium hydroxide. You have 37 g of sodium hydroxide, how many mL of water do you
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Answer #1

Concentration = 127 mM = 127×10-3 M

Moles = mass/molar mass

= 37/40 = 0.925 moles

Volume of solution, V = moles×1000/molarity

= 0.925×1000/127×10-3 mL

= 7283 mL

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