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A particle is acted on by forces given, in newtons

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Answer #1


F3 = F1 + F2

F3 = 2.77i - 14.2j + 2.98 i + 4.36 j

F3 = (2.77+2.98)i + (-14.2+4.36) j

F3 = 5.5 i - 9.84 j

(a)


x component = 5.75 N

(b)


y component = -9.84 N


(c)


angle = tan^-1(-9.84/5.75)

angle = +300.3 degrees

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