A double slit with a spacing of 0.054 mm between the slits is 1.57 m from a screen.
1.) If yellow light of wavelength 567 nm strikes the double slit, what is the separation between the zeroth- and first-order maxima on the screen? (Answer in meters)
2.) If blue light of wavelength 426 nm strikes the double slit, what is the separation between the second- and fourth-order maxima? (Answer in meters)
1)
The maxima condition for interference is
d sin ( theta ) = m ( lamda )
Y = L tan ( thate )
Fro small angles
m ( Lamda ) / d = Y / L
Y = m ( Lama ) L / d
= ( 1) ( 567 *10^ -9 m ) (1.57 m ) / ( 0.054 *10^ -3 m )
= 0.016 m
2)
Y1 = m ( Lama ) L / d
= ( 4) ( 426 *10^ -9 m ) (1.57 m ) / ( 0.054 *10^ -3 m )
= 0.0495 m
Y2 = m ( Lama ) L / d
= ( 2) ( 426 *10^ -9 m ) (1.57 m ) / ( 0.054 *10^ -3 m )
= 0.0247 m
Y1 - Y2 = 0.0495 m - 0.0247 m = 0.0247 m
A double slit with a spacing of 0.054 mm between the slits is 1.57 m from...
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