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30 m 5. The standard test to determine the maximum lateral acceleration of a car is...
A 1200 kg car is practicing on a flat test track. The car begins moving in...
A 1200 kg car is practicing on a flat test track. The car begins moving in a 100 m radius circle at a speed of 20 m/s. Viewed above, it is traveling around the circle clockwise, beginning from the top of the circle. (A) What is the centripetal acceleration of the car? (B) How much force is required for this? (C) What is the coefficient of friction between the tires and the track? Three quarters of the way around the...
1. A 1200 kg car is practicing on a flat test track. The car begins moving...
1. A 1200 kg car is practicing on a flat test track. The car begins moving in a 100 m radius circle at a speed of 20 m/s. Viewed above, it is traveling around the circle clockwise, beginning from the top of the circle. (A) What is the centripetal acceleration of the car? (B) How much force is required for this? (C) What is the coefficient of friction between the tires and the track? Three quarters of the way around...
Spy Agent 001 is chasing the bad guys. Suddenly, 001 needs to turn his car (m...
Spy Agent 001 is chasing the bad guys. Suddenly, 001 needs to turn his car (m = 1000 kg) around, and completes a turn in the shape of a semi-circle (radius = 60 m) travelling at a constant speed of 27 m/s. a) If the static coefficient of friction between the tires and the pavement is 0.55, find the maximum force of friction before slipping occurs. b) Will the car be able to complete the turn without sliding? c) To...
A 960-kg race car can drive around an unbanked turn at a maximum speed of 45...
A 960-kg race car can drive around an unbanked turn at a maximum speed of 45 m/s without slipping. The turn has a radius of 160 m. Air flowing over the car's wing exerts a downward-pointing force (called the downforce) of 13000 N on the car. (a) What is the coefficient of static friction between the track and the car's tires? (b) What would be the maximum speed if no downforce acted on the car?
A 810-kg race car can drive around an unbanked turn at a maximum speed of 40...
A 810-kg race car can drive around an unbanked turn at a maximum speed of 40 m/s without slipping. The turn has a radius of 120 m. Air flowing over the car's wing exerts a downward-pointing force (called the downforce) of 9200 N on the car. What is the coefficient of static friction between the track and the car's tires? What would be the maximum speed if no downforce acted on the car?
A 860-kg race car can drive around an unbanked turn at a maximum speed of 44...
A 860-kg race car can drive around an unbanked turn at a maximum speed of 44 m/s without slipping. The turn has a radius of 140 m. Air flowing over the car's wing exerts a downward-pointing force (called the downforce) of 11000 N on the car. (a) What is the coefficient of static friction between the track and the car's tires? (b) What would be the maximum speed if no downforce acted on the car?
A 900-kg race car can drive around an unbanked turn at a maximum speed of 42...
A 900-kg race car can drive around an unbanked turn at a maximum speed of 42 m/s without slipping. The turn has a radius of 170 m. Air flowing over the car's wing exerts a downward-pointing force (called the downforce) of 10000 N on the car. (a) What is the coefficient of static friction between the track and the car's tires? (b) What would be the maximum speed if no downforce acted on the car?
Calculate the maximum acceleration (in m/s2) of a car that is heading down a 6.290 slope...
Calculate the maximum acceleration (in m/s2) of a car that is heading down a 6.290 slope (one that makes an angle of 6.290 with the horizontal) under the following road conditions. You may assume that the weight of the car is evenly distributed on all four tires and that the static coefficient of friction is involved-that is, the tires are not allowed to slip during the acceleration. (Ignore rolling friction. Assume the positive direction is down the slope. Indicate the...
A car travels at a speed of 21 m/s around a curve of 27 m. m...
A car travels at a speed of 21 m/s around a curve of 27 m. m = 1500 kg (i) What is the net centripetal force needed to keep the car from skidding sideways? (ii) Were there no friction between the car’s tires and the road, what centripetal force would be provided just by banking the road at 29o? (iii) Now, suppose a friction force is also present and prevents the car from skidding. Calculate the magnitude of the normal...
A car travels at constant speed around a corner. The cars speed is 35 m/s and...
A car travels at constant speed around a corner. The cars speed is 35 m/s and the radius of the circle is 0.25 km. The coefficient of static friction between the tires and the road is 0.7. What is the frictional force needed for the car to make the turn? What is the maximum force the static friction can produce? Does the car stay on the road? The car is in motion so why is the static friction important?
A 810-kg race car can drive around an unbanked turn at a maximum speed of 40 m/s without slipping. The turn has a radius of 120 m. Air flowing over the car's wing exerts a downward-pointing force (called the downforce) of 9200 N on the car. What is the coefficient of static friction between the track and the car's tires? What would be the maximum speed if no downforce acted on the car?
Calculate the maximum acceleration (in m/s2) of a car that is heading down a 6.290 slope (one that makes an angle of 6.290 with the horizontal) under the following road conditions. You may assume that the weight of the car is evenly distributed on all four tires and that the static coefficient of friction is involved-that is, the tires are not allowed to slip during the acceleration. (Ignore rolling friction. Assume the positive direction is down the slope. Indicate the...
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