Given the following information for octane (114.26 g/mol), calculate the total amount of heat absorbed when...

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Answer 1

Answer #1

Since melting point - 56.8 ⁰C and we are asked to calculate from 20 degree C, it indicates that the compound is in liquid state.

q1 = m * s * (t2-t1)lquid

q₁ = Heat change occured from - 20 to 125.7 degree C=(540/114.6)*254.6*(125.7+20) = 174794. J

q₂ = heat of vaporisation = (540/114.6) * 41500 = 195550. J

q₃ = Heat change occured from 125.7 to 145 degreeC = (540/114.6) * 316.9 * (145 - 125.7) = 28820.J

Total heat change = q₁ + q₂ + q₃ = 399164 J = 399.kJ

Answer 2

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