The solution of the above question is given below with explanation.
Compound (I) is a secondary alkyl halide because the Carbon at which the Iodine atom is attached has two adjacent carbon bonded to it.Hence it is secondary alkyl halide.
Compound (II) is a primary alkyl halide because the Carbon at which the Br atom is attached has only one adjacent carbon bonded to it.
Compound (III) is a tertiary alkyl halide because the Carbon at which the Cl atom is bonded has three more adjacent Carbon atoms attached to it.Hence it is tertiory alkyl halide.
Compound (IV) is a secondary alkyl halide because the Carbon at which the Br atom is attached has two adjacent carbon atoms bonded with it.Hence it secondary alkyl halide .
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