Question

9. How do you prepare a 1 L solution of 0.1 M HCl from a 12 M HCl solution? Don't just do the calculation but explain HOW you would actually make this solution, which equipment you would use, and what protocols/procedures you would follow to ensure the appropriate concentration of the diluted solution. (14 points)

Answer 1

According to Dilution formula:

M1V1 = M2V2                    M1 = 12 M , V1 = ?         M2 = 0.1 M , V2 = 1L    (1L = 1000 mL)

12*V1 = 0.1*1

V1 = 0.0083 L

      = 8.3 mL

Volume of water added = V2 - V1 => 1000 - 8.3 = 991.7 mL

Initially by taking 8.3 mL of 12 M HCl solution, to this add 991.7 mL of water to make final volume of 1000 mL.