Problem 7.48 i</ 100111 solid cylinder with a 0.30 m radius, has a rope going over...

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Answer 1

Answer #1

Given , T1 = 12 N, T2 = 10 N, m = 0.85 kg, r = 0.3 m Now , moment of inertia of pulley(1) : | = (1/2)*m*r^2 = (1/2)*0.85*0.3^

Answer 2

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