Question

The reaction below is an elementary reaction. What is the rate law of the reaction? Ca++ (aq) + Mn2+ (aq) → Ce+ (aq) + Mn3+ (aq) Rate = k[Cet] [Mn2+1 Rate = k[Ce**1? [Mn2+12 Rate = k[Ce 4+][Mn2-12 Rate = k[Ce**]? [Mn?")

Answer 1

To find rate law of elementary step we have to focus of on Concentration of reactant not on the concentration of product. Molecularity Elementary | Rate law Step A products rate= K[A A+ A- Products rate= K[A² A+B Products rote = K[A][b]

for elementary reaction, Got (aq) + Mn2+ (aq) — Cest (aq) + Mn3t (aq) The rate law of the reaction is Rate = K [ce^+] [Mm24]