calculate the number of equivalents of sulfonic acid present in 100 mg of resin, knowing that...
calculate the number of equivalents of sulfonic acid present in 100 mg of resin, knowing that the concentration of sulfonic groups in the Nafion resin is 0.8 milliequivalent/g of resin.
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calculate the number of equivalents of sulfonic acid present in
100 mg of resin, knowing that...
2. The structure of the solid phase Wang resin linker and the first amino acid that we will use i...
2. The structure of the solid phase Wang resin linker and the first amino acid that we will use in this lab is shown below Fmoc first amino acid linker a) (1 pt) If the resin has 0.72 mmol/g of this linker on the surface of the beads, and you use 300 mg of resin for the reaction, how many mmol of linker do you have? b) (3 pts) All peptides will use alanine at the C-tenminus (position 1), Fmoc-L-valine...
Question 20 of 32 > A 1.069 g sample of N-2-acetamido-2-aminoethane-sulfonic acid potassium salt (ACES K'....
Question 20 of 32 > A 1.069 g sample of N-2-acetamido-2-aminoethane-sulfonic acid potassium salt (ACES K'. MW = 220.29 g/mol) is dissolved in 87.54 mL of water. To the solution, 11.62 mL of HC is added, resulting in a pH of 7.42. Calculate the concentration of the HCl solution. The pk, of ACES is 6.85. [HC] = MacBook Pro 8 90
A 1.986 g sample of N-2-acetamido-2-aminoethane-sulfonic acid potassium salt ( ACES − K + , MW...
A 1.986 g sample of N-2-acetamido-2-aminoethane-sulfonic acid potassium salt ( ACES − K + , MW = 220.29 g/mol) is dissolved in 73.73 mL of water.To the solution, 14.73 mL of HCl is added, resulting in a pH of 6.56 . Calculate the concentration of the HCl solution. The p K a of ACES is 6.85.
The cation content of a water sample is determined by exchanging the cations for protons on stron...
The cation content of a water sample is determined by exchanging the cations for protons on strong acid and ion-exchange resin. An 25 mL sample was added to a 2 g resin. After reaching equilibrium the resin is filtered off and the solution titrated with alkali. 18 mL of 0.020 M NaOH are required to reach the endpoint. Calculate the normal concentration of cations ( the number of equivalents present in 1 L of sample).Your answer must be in order...
1.800 g of N-2-acetamido-2-aminoethane-sulfonic acid potassium salt (ACES–K , MW = 220.29 g/mol) is dissolved in...
1.800 g of N-2-acetamido-2-aminoethane-sulfonic acid potassium salt (ACES–K , MW = 220.29 g/mol) is dissolved in 89.94 mL of water. 29.91 mL of HCl is added to the solution, resulting in a pH of 7.24. Calculate the concentration of the HCl solution. The pKa of ACES is 6.85.
A 1.944 g sample of N-2-acetamido-2-aminoethane-sulfonic acid potassium salt (ACES-K+, MW = 220.29 g/mol) is dissolved...
A 1.944 g sample of N-2-acetamido-2-aminoethane-sulfonic acid potassium salt (ACES-K+, MW = 220.29 g/mol) is dissolved in 52.38 mL of water. To the solution, 27.66 mL of HCl is added, resulting in a pH of 6.95. Calculate the concentration of the HCl solution. The pK, of ACES is 6.85. (HCI) = 3.80 x10-6
calculate the number of equivalents. 0.8 mole of Mg2+ Express your answer using one significant figure.
calculate the number of equivalents.
0.8 mole of Mg2+ Express your answer using one significant figure.
Assume that you have a stock solution of epinephrine at a concentration of 3 mg/mL. Knowing...
Assume that you have a stock solution of epinephrine at a concentration of 3 mg/mL. Knowing that the pipette you will use delivers 20 drops/mL, calculate the number of drops of the stock solution that must be added to a smooth muscle bath containing 27 mL of Locke’s solution so that the final concentration of epinephrine in the muscle bath will be 173 µg/mL.
Calculate the number of grams of acetic acid needed to prepare 100. mL of 1.00 M...
Calculate the number of grams of acetic acid needed to prepare 100. mL of 1.00 M acetic acid. The molecular weight of acetic acid is 60.1 g/mol.
Calculate the number of moles and the mass of negative ions present in 15.67 g of...
Calculate the number of moles and the mass of negative ions present in 15.67 g of magnesium nitrate, Mg(NO3)2.
2. The structure of the solid phase Wang resin linker and the first amino acid that we will use in this lab is shown below Fmoc first amino acid linker a) (1 pt) If the resin has 0.72 mmol/g of this linker on the surface of the beads, and you use 300 mg of resin for the reaction, how many mmol of linker do you have? b) (3 pts) All peptides will use alanine at the C-tenminus (position 1), Fmoc-L-valine...
Question 20 of 32 > A 1.069 g sample of N-2-acetamido-2-aminoethane-sulfonic acid potassium salt (ACES K'. MW = 220.29 g/mol) is dissolved in 87.54 mL of water. To the solution, 11.62 mL of HC is added, resulting in a pH of 7.42. Calculate the concentration of the HCl solution. The pk, of ACES is 6.85. [HC] = MacBook Pro 8 90
A 1.944 g sample of N-2-acetamido-2-aminoethane-sulfonic acid potassium salt (ACES-K+, MW = 220.29 g/mol) is dissolved in 52.38 mL of water. To the solution, 27.66 mL of HCl is added, resulting in a pH of 6.95. Calculate the concentration of the HCl solution. The pK, of ACES is 6.85. (HCI) = 3.80 x10-6
calculate the number of equivalents.
0.8 mole of Mg2+ Express your answer using one significant figure.
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