At a certain temperature, the K_p for the decomposition of H_2S is 0.754. H_2S(g) H_2(g) +...

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Question

Answer 1

Answer #1

So we have got the partial pressure of H₂ and S at equilibrium

Partial Pressure of H₂ = S = 0.121 atm

Partial Pressure of H₂S at equilibrium = 0.141 - 0.121 = 0.02 atm

So total pressure at equilbrium = 2 * 0.121 + 0.02 = 0.242 + 0.02 = 0.262 atm

Thank You

Answer 2

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