Ca3(PO4)2 (s) <---> 3Ca2+ (aq) + 2PO4^3- (aq)
Ksp = [Ca2+]^3 [PO4^3-]^2 , where Ksp = 10^- pKsp = 10^-26
10^-26 = [Ca+]^2 ( 10^-6)^2
[Ca2+] = 10^-7 M , per 1L we have Ca2+ moles = 10^-7 mol
Ca2+ mass = moles x atomic mass of Ca2+
= 10^-7 mol x 40g/mol = 4 x 10^-6 g = 4 x 10^-6 x 10^3 mg = 4 x 10^3 mg
Thus Ca2+ concentration = 4000 mg/L
CaCO3 moles = ca moles = 10^-7
CaCO3 mass = moles x molar mass of CaCO3 = 10^-7 mol x 100 g/mol = 10^-5 g = 10^-5 x 10^3 mg
= 0.01 g
Thus CaCO3 concentration needed = 0.01 mg/L
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