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IDC 10V a. Determine VTH for the unknown component b. Determine RTH for the unknown component. c. Determine IN for the unknow

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a. VTH = 5 V b. RTHERN = 20 c. In = 250 mA d. Thevenin Equivalent Circuit e. Norton Equivalent Circuit 2022 250mA = 5v 13 3 2
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Answer #1

lov - € 10. A 5 @ Uth Thevening Voltage at & uth - - blio 5 lov By loop Analysis Neglected because I Nocurrent flows throug hRth Thevenine Resistance rrent sources are shorted cofrest Voltage source are opened 2 م به low SN 151 lonis sarallel with shfrom loop 10 = 109. - loigio from loop @ lo 2₂-102, +512- 5 Iz + 15 12=0 3012 -1091 – 512 zo. from loop ③ 13=-14 becuse corre@ Thevening fruilent circuit Rth 20 N th=5 (e Nortons equilent circuit IN=250mA 1 Rth- W X1 a Tab 5vL lov - & lone 5s / 15 ~Apply KvL to above loop. 8.-201-= 0 20I zo Izoal

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