A 40 kg mass is attached to a cable wound around a 0.5 m diameter wheel of mass 5 kg (I = MR2), and released from rest. What is the velocity of the mass after it drops a distance of 4 m?
Inertia=MR2=5*0.25*0.25=5/16
torque=40*g*0.25=98Nm
torque=inertia*angular acc
ang acc=98*16/5=313.5
w2=02+2*313.5*4
w=50
v=wr=50*0.25=12.5 m/s
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