Question

B. 0.20 M C. 5.0 M D. 100M 100. A 250-ml sample of a 0.250 M glucose solution contains how much glucose? Glucose has a molar mass of 180 g/mol A. 11,2505 B. 180 C. 2.888 D. 1123 101. A salt solution is made by adding 25.5 g of salt to 135 ml of solution. What is the [w/v) of the salt solution? A. 18.9% B. 5.29% C. 110% D. 15.9% 102. How much of a 35.0X(w/v) glucose solution would be needed to make 700 mL of a 1.50%(w/v) glucose solution? A. 163 mi B. 16.3 mL C. 300 ml D. 300 ml 103. Which is an example of a colloid? A salt water B. a mixture of mineral oil and gasoline chomogenized whole milk D. muddy water and the freezing point 104. When sugar is added to water, the boiling point A decreases, decreases B. decreases, increases C. increases, decreases D. increases, increases 105. Which solution has the lowest freezing point? A. 10M KOH B. 1.0 M CHOH (ethanol) C. 1.0 M Naci D. 1.0 M NA SO 106. In which solution would a blood cell be the most stable? A hypotonic B. Isotonic C. hypertonic

Answer 1

100.Ans :-

Given volume of the sample = 250 mL = 0.250 L

Molarity of glucose solution = 0.250 M

As, Molarity = Number of moles/ Volume in L

Therefore,

Number of moles of glucose = Molarity x Volume in L

= 0.250 M x 0.250 L

= 0.0625 mol

Mass of glucose = Number of moles of glucose x Gram molra mass of glucose

= 0.0625 mol x 180 g / mol

= 11.250 g

Therefore, option (D) i.e. 11.2 g is the answer.

101.Ans:-

Weight/volumw (w/v) percent = Weight of salt x 100% / Volume

= 25.5 g x 100% / 135 mL

= 18.9%

Therefore, option (A) i.e. 18.9% is the answer.