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determine the value of the reaction at the supports including the internal hinge of the frames
If supports A and B have only vertical reaction. Determine the resultant internal loadings acting on the cross section at C of the beam shown in the figure. ).5 kN/m
You have to break up the beams at the internal hinge. Determine the reactions at A and C. B is an internal hinge. 800 lb 500 lb 300 lb-ft 4 ft 2 ft 200 lb 8 ft MA Ax ve 4C1 26A
For Problems 6.66 through 6.79, draw the shear and moment diagrams for the frames shown. Both supports are pin supports. (Ans: max V=-78.5 k, max M = 1339 kft) P6.71 80 k 13 50 k 30ft 10 ft Problem 6.71 (Ans: max V=-78.5 k, max M = 1339 kft) P6.71 80 k 13 50 k 30ft 10 ft Problem 6.71
2) A beam supports the loading shown below. Determine the internal normal force, shear force and beading moment acting just to the left of point B and to the right of point C of the 8 kN force. 8 KN loknom A D oo 6 ) B C 2m 5m 1
2) A beam supports the loading shown below. Determine the internal normal force, shear force and beading moment acting just to the left of point B and to the right of point Cof the 8 kN force. 8 KN loknom A D t 0 0 B C 5m
Determine the reactions Ay and By at the supports A and B, respectively. Reaction By 2 kft 12 k.ft B 6 Itt 02.8 6.5 O 0.7
The following sections belong to two frames with different supports: Compare the slabs in frame A and B in terms of h and As (for example ha<hand Asa<Asg)(10 points). -22.50 m 12.40 km 0-22.50 m 12.40 km А B -0.40m -0.40m
20 point the feed to determine the reaction at the supports, drew the show and moment diam. Assume A is fixed and is a roller. El is constant the shear and moment diagrams on your hand call sheet Loading 1 + Equation + PL ЗЕ/ at x2 0.. = PL 2ET - GET (2 – 3Lx?) at x L L MacBook Air A Quinta HY PZ 27 atr=L Sen - 3Lx) isk A 10'6" Floº - MacBook Air 8 /R7...
Question 1 (30 points) Hinge Hinge Draw the influence lines for A) reaction moment at G b) shear and bending moment at E c) Determine the maximum positive and negative shears and the maximum positive and negative bending moments at point E due to (i concentrated live load of 160 kN, (ii) uniformly distributed live load of 28 kN/m with 2 m length