`Hey,
Note: Brother if you have any queries related the answer please do comment. I would be very happy to resolve all your queries.
1) It can be written as
=12*(2*n^2-n)=theta(n^2)
2) It can be written as
=theta(n^9)
3)
It is theta(n*log(n^3))=theta(n*log(n)) since the inner loop is increasing j by multiplying with 5.
Kindly revert for any queries
Thanks.
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