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calculate ksp at 298 K for AgCl given E^01/2= 0.22 V for AgCl(s) + e- =...

calculate ksp at 298 K for AgCl given E^01/2= 0.22 V for AgCl(s) + e- = Ag(s) + Cl-(aq)
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Question is solved using concepts of electrochemistry.

Solution- Criven data are Ag olcs) te A90) cicaq) Ez 0-221 ☺ And the standard reduction potential of Agt is as - Agt te → AgAGZ AG + RT INR at equilibrium Q z k Oz -N FE° + RT luk AFE® z RT en [Ag+] [41] NFE Z RT en Ksp Inksp z RT NFE z LX 96500 X (

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