Question

Single pipe with turbine) Water drains from a pressurized tank through a pipe system as shown in the figure below. The head o

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Answer #1

Solution –

Diameter of pipe (D) = 0.1 m

Radius of pipe (R) = 0.05 m

Area of pipe (A) = π * 0.12 / 4 = 0.00785 m2.

Roughness height (K) = 0.001 m

Length of pipe (L) = 200 m

Flow rate = Q

First, we are required to find the friction factor using Nikuradse Formula as shown below,

1 210g,o()+1.74 0g1o +1.74 =

Putting values in the equation, we will get

f = 0.038

Now,

The head loss will be comprising of major head loss in the pipe (HL) and minor head loss in pipe due to sudden expansion (HL-1) and due to pipe bend (HL-2), (HL-3).

(HL) = f*l*Q2 / (12.1 * D5) = 62809.92 * Q2.

(HL-1) = K1*Q2/(2*A2*g) = 421.563 * Q2.

(HL-2) = (HL-3) = K2*Q2/(2*A2*g) = 84.313 * Q2.

Total Head loss = 63400.179 * Q2.

Change in elevation – total head loss = 116

200 – 63400.179 * Q2 = 116

Q = 0.04277 m3/s

So, the flow rate is 0.04277 m3/s.

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