Solution –
Diameter of pipe (D) = 0.1 m
Radius of pipe (R) = 0.05 m
Area of pipe (A) = π * 0.12 / 4 = 0.00785 m2.
Roughness height (K) = 0.001 m
Length of pipe (L) = 200 m
Flow rate = Q
First, we are required to find the friction factor using Nikuradse Formula as shown below,
Putting values in the equation, we will get
f = 0.038
Now,
The head loss will be comprising of major head loss in the pipe (HL) and minor head loss in pipe due to sudden expansion (HL-1) and due to pipe bend (HL-2), (HL-3).
(HL) = f*l*Q2 / (12.1 * D5) = 62809.92 * Q2.
(HL-1) = K1*Q2/(2*A2*g) = 421.563 * Q2.
(HL-2) = (HL-3) = K2*Q2/(2*A2*g) = 84.313 * Q2.
Total Head loss = 63400.179 * Q2.
Change in elevation – total head loss = 116
200 – 63400.179 * Q2 = 116
Q = 0.04277 m3/s
So, the flow rate is 0.04277 m3/s.
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