Question

HW 2B - PHY 251, section 2110, X C An Attacker At The Base Of A Ca: x + - 0 % E → C webassign.net/web/Student/Assignment-Responses/submit?dep=215373248_tags=autosave 47.2 m Need Help? Read It Watch It 6. 0/4 points Previous Answers SerPSET9 2.P.045. My Notes A gymnast jumps straight up, with her center of mass moving at 5.87 m/s as she leaves the ground. How high above this point is her center of mass at the following times? (Ignore the effects of air resistance, and assume the initial height of her center of mass is at y = 0.) |t(s) y (m) 0.100 Your response differs from the correct answer by more than 10%. Double check your calculations. Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. x 0.300 Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. 0.500 Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. Need Help? Read It Submit Answer Practice Another Version 7. + 3.2/5 points Previous Answers SerPSET9 2.P.046. My Notes An attacker at the base of a castle wall 3.60 m high throws a rock straight up with speed 8.60 m/s from a height of 1.50 m above the ground. 12 Be ô a co 9 A O 3:09 PM 1) 3/30/2019 W

Answer 1

10=5.07 x-vot - 42-9.8 gtz No 1 = 5.87001- 1 x 98 x 10.112 - 053) m No.2-5-87802 - 1 x 9.0 (0.212 1 2 > 0978 103 = 5.978 0.3 - 89:88 (0.3) 2 = 132 m 10.5= 5.87X0.5-1898x10.52 - 171m