7. A sample of gas occupies a volume of 6.63 L. when the gas is allowed...

Question

Question

Answer 1

Answer #1

Here, both the pressure (P) and temperature are constant. Thus, work done will be,

W = P(V2 - V1)

1 L-atm = 101.325 J

Work, W = 1001 J = 1001 J x (1L-atm/ 101.325 J) = 9.879 L-atm

Initial Volume, V₁ = 6.63 L

Final Volume, V₂ = ?

Thus, using the expression for work, we have,

9.879L • atm = (1.5latm) (V2 - 6.63L) V2= 13.17L

Answer 2

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