Question

Shown below is a waterslide constructed in the late 1800's. This slide was unique for its time due to the fact that a large number of small wheels along its length made friction negligible. Riders rode a small sled down the chute which ended with a horizontal section that caused the sled and rider to skim across the water much like a flat pebble. The chute was 9.76 m high at the top and 54.3 m long. Consider a rider and sled with a combined mass of 75.5 kg. They are pushed off the top of the slide from point A with a speed of 2.90 m/s, and they skim horizontally across the water a distance of 50 m before coming to rest. Engraving from Santific American July 1888 20.0 m 0.76 m -54.3 m 50.0 m (b) (a) Find the speed (in m/s) of the sled and rider at point C. m/s (b) Model the force of water friction as a constant retarding force acting on a particle. Find the magnitude (in N) of the friction force the water exerts on the sled. (c) Find the magnitude (in N) of the force the chute exerts on the sled at point B. (d) At point C the chute is horizontal but curving in the vertical plane. Assume its radius of curvature is 20.0 m. Find the force (in N) the chute exerts on the sled at point C. magnitude direction ---Select-

Answer 1

For wort energy theorer work don – change in kinetic energy. ugravity & Whorend & murmur Kgh+ 0 & 12 x (v - gh = ₂ ( v ) 9.8* 9.76= 6 - 2.50) N2 = 14.13 1 m/s) velocity of parke work done due to water boven - OKE - F.450 = m( - ) - FX50 = 75.5 (0- 14.131) T = 150077 & friction force due to calor (1) ing =755(9.8) cos 10.354 = 727.85N N=mgaso 54.3 9.76 silo- 9.76 sino 54.3 Or 10.354 not force=ma New to a 2nd low N-mg=ma N-95.505.8) = 75.5(14.131") 20 (N = 1493714 upwards