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The 3.5-kg cart, at rest at time t = 0, is acted on by a horizontal force which varies with time t as shown. Neglect friction

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Answer #1

F = K +2 parabolic SO F= 25 N, when t = 21 sec 25 =k, = ķi Kz 5.6689 N/S2 (2011 2 SO F = 5.6689 t2 so te lol see myo + F dtmv = དང ་འ བྱ བ རྒྱ་བཟའ་ 5• ༠༦ eཤx 2•ད 3 + 3o-45675 Vདང།3，8447 /sez

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