Question

Page |182 POSTLAB QUESTIONS . In the experiment PART B did you achieve neutralization with 30 drops of 0.10 M NaOH solution? If not, explain why. is needed to prepare 500.0 mL of a 0.75 M K2S04 solution? 2. What mass of K2SO4 K 39; S 32; O-16 . What volume of water is needed to dilute a 25 mL of a 5.0 M sugar solution to obtain a 1.0 M ugar solution?

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Answer 1

1 drop = 0.05 ml 30 drops = 30 times 0.05 = 1.5 ml 1.5 ml of 0.10 M Na OH = 0.0015 L times 0.10 mole/L = 0.00015 mole therefore During neutralization, 0.00015 mole acid required Yes, you can achieve if experiment leads to 0.00015 mole mono protic acid. Otherwise not possible. Molar mass of K_2 SO_4 = (2 times 39 + 32 + 4 times 16) = 174 g/mole 500.0 ml of 0.75 M K_2SO_4 = 0.500 times 0.75 = 0.375 moles Mass of K_2 SO_4 = 0.375 mole times 174 g/mole = 65.25 g V_1 S_1 = V_2 S_2 25 times 5.0 = V_2 times 1.0 v_2 = 125 ml Volume of 1.0 M Solution = 125 ml V_2 = 125 ml volume of water needed = (125 - 25) = 100 ml