Question

Question 1 In the circuit shown below, determine the magnitude and direction of current flow through each resistor using KVL and KCL. [5 points]. If point A is grounded, what is the potential at point B? [1 point] If a shorting wire is connected between A and B, what power is dissipated in the 5 12 resistor? [2 points] 223 5v 322 1.5V 322

Answer 1

s a By using kve §su 22 5v - 2 These two resistors are connected in parallel Svo Sr 22 1.52 r.sm -5+5 It is -15V +91=0 8.51 = 6.5V T= 0.76A and lisr is o.16A current through desi stors, 25, 52 1x1.52= lryzv V3R = By using lock :- GLMT 31 .5V MA 32 € node VB Apply toch at VB-(-5)-(-15) S teve het eveno 7 ve [att + 1) = -2 Tuge -1.1470]

current through registo88 52 and an and art and 3r Izn = 15e (vo +6.5)v 13.2 = 13.1. Ota to dot1:147)v 1152 Isr=dan = 0.76470 7 : (-1,147+6.5) V Ise=132= 0.7647 A Ve= .147 VA is a rounded Then 3) § 2o sv SM 31 _M 1.5V 32 I --- = These three registoos are Connected in parallel So short circited SV S2 - ร่ Apply (ve to 10OPO 1 = 0.928A power is disspared by sur desistors Psr= Ihr = (0.9285x5 Pse = 4.32 Watts