Question

In a steam power cycle shown in the figure, the pressure of the water vapor exiting from the boiler with 1 kg mass at 1 point is P1 = 4 MPa, while the temperature is T1 = 400 oC, the pressures at the inlet and outlet of the mixing chamber (K.O.) are P2 = P3 = P4 = 1 MPa. The temperature at the inlet of the low pressure turbine (A.B.T.) is measured as T4 = 240 oC and the pressure at the outlet is P5 = 10 kPa. The degree of dryness at point 6 is X6 = 0.0. The temperature values at the inlet and outlet of the feed water heater (B.S.I.) are T8 = 160 oC and T9 = 200 oC, and the efficiency of the pump (P), low pressure turbine and high pressure turbine (Y.B.T.) are P = 1.0; ABT = 0.9; YBT = 1.0. K.V. It is a throttling valve.
a) Show the cycle in diagram T-s and h-s
b) Find masses m1, m2, m3, m4 (kg).
c) Calculate the thermal efficiency of the cycle.

Kazan 1kg m3 m2 Y.B.T KV m 1 on B.S. 3 2 K.O. B 4 Yüzeyli Tip B.$.1 m4 A.B.T Zkv. Yogusturucu 5 my

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Answer #1

T 4MB Tut (1-man LA m 2 I MPa hun li-m, med loupe 6 11-m) is the mail S S

Please give some positive rating.. I have less CF Score

Thank you so much TES (-) m2 1 m1 YOT Xv. m3= 1- m - m2) K.O. BS e-my Yuzey Tip B51 m2 MA (1-m-ma) my Авт Xry Yopusturucu (l-m) my (i-m-ma) 4 Mistaky = 6. 88117 millega Pueuwe (Paul = 1 MPa. Temperdure (Tow) = 2400 wat 1MPa the datumshion Temp, Teat: 1979.90 vomid SinEffecemnicy of ART Vent) =09 Ang hu hs -> 0.9 2920.4 - hs 2920.4-2177.91 hy-hiss hs = 2252. 159 «slleg estate 1-0102 x1033 miStika Prienuorellal: 4M for Temperature (tg) = 200°C wat 4Mva aturation temp Treat - 250.4-c che, abe-9.aubcooled biquid enthMg = (1-m, m₂) my -(1-0.07-0.148) 0.782 kg m₂ = Now lly for the Yuzelli tip BI mulhy-ho) = (1-mul ha-ha) maa 11-004)(675.55-

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