Question

A granular sample is proposed for highway base-course construction. Test results are Retained 0g Sieve 25 mm (1 in.) 19 mm (3
The fine aggregate from the pan was split down to 513.4 g and washed. Loss in washing was 29.9 g. Results of fine sieving wer
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Answer #1
  • TO calculate the gradation we have to find the value of Cu & Cc .
  • 1st prepare a chart that represent % passing through sieve.
  • sieve size(mm) weight retained(g) weight passed(g) %passing (%finess)
    4.75 0 482.4 100
    2.00 80.6 401.8 83.3
    1.18 122.0 279.8 58.0
    0.60 52.3 227.5 47.16
    0.425 35.1 192.4 39.88
    0.150 101.4 91 18.86
    0.075 83.7 7.3 1.51
    pan 7.3 - -
    total weight =482.4
  • formula-

  • C^{u}=\frac{D_{60}}{D_{10}}

  • C_{c}=\frac{D_{30}^{2}}{D_{60}\times D_{10}}

  • we have to caculate the value of D60,D10&D30  by linear interpolation from chart as following

Die = 0.0751 0.150 -0.075 78.86 -2.57*(18-86-10) + Dio = 0·113 mm mm 0.425 -0.150 Dizo = 0.150 + 39.88 -18.8T X / 39.88 - 30grain size distribution curve

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FOR acceptance of material as per ASTM-

The amount of the fraction of material passing the No. 200 mesh sieve shall not exceed one-half the fraction passing the No. 40 mesh sieve.

ONE HALF OF FRACTION PASSING 40MESH SIEVE =39.88/2=19.9 WHICH IS GREATER THAN FRACTION PASSING THROUGH 200MESH SIEVE (1.51). HENCE IT CAN BE USED AS BASE COURSE ACCORDING TO ASTM.

BUT according to aastho claaassifiation-

  1. For gradings C, D, and E, at least 50% by weight of the particles retained on the No. 4 sieve.
  2. For gradings C-1, D-1, and E-1, at least 70% by weight of the particles retained on a No. 4 sieve.

but here 100% passing through sieve no-4 henceit is not suitable for base course material.

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