Question

1) Write equilibrium expressions (Kg and K) for each of the following unbalanced equations: CaSO,(s) CaO s)+ SO2(8)+ 02(g CH,COO (aq) + H20 (aq) C H,COOH(aq) + H2O(I) 2) The reaction 2HBr(g) H2(g)+ Br2(g) has a Ke value of 1.05 at 25°C. If [HBr] = 0.177 M, [H] 0.223 M and [Br] =0.111 M, in which direction will the system shift?

Answer 1

Solution-I The giren chemical equation is - Gasoy (s) = Cors) + sog g) +8099 The balanced chemical equation is - 2 Casoy (s) = 2 Co(s) +250, 9) + O g) The equillibrium constant for the above equation is written as | ke = [Cao G]* [S9, 90° | 2, 3 [casou (6) 2 In this equation [ cao (s)] & [caso, (s)] is taken as - Il for pure solid and pure liquid the molar concentration a is constant ] Hence, modified equillibrium constant is - Kc = [S, G3] [og]] For kp - As we know, kp = kc (RT) Ang Here Ang = No. of moles of gaseous produck - No. of modes of goscous creactant Ang = 3 kp = kc (RT)3 kp = [50, G))[0, Gu(R113 Scanned with CamScanner

The giren equation is – CHE COOH Caq) + H2O(l) = CHC00(aq) + Hot Came] C (balanced equation ) k = [GH1-c00" p)) ( 1,062 [Gmg coo H Cap:)) ( 14000] The nela concentration of perla liquid if I Kc = [cally cooº caq.) J (Hot] [Ghis coolt Cap:)] As we know, that kp=ki(41) ling Ang = No. of modes of gove su products - No. of malway Bry=0 gwest coatienten k = k(6)^ Kp = ke (Rs)' = Kc M = [lite (00029.27 [Hz ot (aq)] [ Colts cool Tap:)] Scanned with CamScanner

do. Solution-2 The given chemical equation is 1. Q HBr (9) Hogl + Bra (g) The equilibrium constant for the giren equation- de les = [He go] [ Brego] (HBr guja? To determine the direction of any reaction we at dostate any stage we calculate & [ reaction quotiert] le.de is molar concentration ] Qc = kc → No net reaction occur de >kc Net readion goes backward direction. de cka Kc = 1.05 OC 0.223 x 0111 10177)2 #f → goes in forward direction. Net reaction (giren) 0.024753 0.031329 Q = 0.7900 the net reaction goes Hence in forward de <kc direction. Scanned with CamScanner