To balance seesaw, net torque should be 0.
let,
w1=weight of the mother=75 x 9.8 N
w2=weight of the daughter=15 x 9.8 N
r1,r2 be the distance of mother and daughter from the center respectively.
therefore, t1=torque of the mother's weight at center=w1 x r1
t2=torque of the daughter's weight at center= w2 r2
to balance the seesaw,
t1 = t2
w1 x r1 =w2 x r2
75 x 9.8 x r1 = 15 x 9.8 x 1.5
r1=(15 x 1.5)/(75)=0.3
therefore mothere should sit at 0.3m distance from the center to balance the seesaw
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