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The project manager of Good Public Relations gathered the data shown in the following table for a new advertising campaign. C

Activity Optimistic Time Estimates (weeks) Most Likely Pessimistic Immediate Predecessor(s) START START START = C-ITMOOO) NWN

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For each activity, calculate the expected time u =(a + 4m+b)/6 For each activity, Variance oʻ =(b-a)/36. Standard deviation o

c)

Expected time of path A-E-G-H-J = 10.17+9.83+3.00+4.67+5.17 = 32.83

Variance of path A-E-G-H-J = 0.25+0.69+0.44+1.00+0.69 = 3.08

Standard deviation = sqrt(3.08) = 1.76

z = (36-32.83)/1.76 = 1.80

P(z) = NORMSDIST(1.80) = 0.9643

Probability that path A-E-G-H-J will exceed the expected project duration = 1 - 0.9643 = 0.0357

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