Answer is F2.
Strongest Oxidizing agent is one which get reduced easily and whose reduction potential is positive. Since, F2 has highest reduction potential thus it is strongest Oxidizing agent.
Consider the following standard reduction potentials in acid solution: E(V) -2.93 Ke- Lim + - LA...
Consider the following standard reduction potentials in acid solution:E^o(V)Al3+ + 3e– ? Al(s) –1.66AgBr(s) + e– ? Ag(s) + Br– +0.07Sn4+ + 2e– ? Sn2+ +0.14Fe3+ + e– ? Fe2+ +0.77The strongest reducing agent among those shown above is
Given: 2H+(aq)+2e– ⇌H2(g);E°=0.00 Li+(aq)+e– ⇌Li(s);E°=–3.04V F2(g)+2e– ⇌2F–(aq);E°=2.87 Al3+(aq)+3e– ⇌Al(s);E°=–1.66V Pb2+(aq)+2e– ⇌Pb(s);E°=–0.13V Under standard-state conditions, which is the strongest oxidizing agent? Select one: a. Pb2+ b. Al3+ c. F2 d. Li+ e.H+
Consider the following half-reactions: Half-reaction E° (V) F2(g) +2e - →2F (aq) 2.870V 2H*(aq) + 2e - H2(g) 0.000V Cr3+ (aq) + 3e — Cr(s) -0.740V (1) The strongest oxidizing agent is: enter formula (2) The weakest oxidizing agent is: (3) The weakest reducing agent is: (4) The strongest reducing agent is: (5) Will F2(g) oxidize Cr(s) to Cr3+ (aq)? (6) Which species can be oxidized by H(aq)? If none, leave box blank.
Table 20.1 Half Reaction E°(V). F2 (g) + 2e →2F (aq) +2.87 Cl2 (g) + 2e → 2CV (aq) +1.359 Br2 (1) + 2e → 2Br (aq) +1.065 O2 (g) + 4H+ (aq) + 4e → 2H20 (1)+1.23 Agt te → Ag (s) +0.799 Fe3+ (aq) + € → Fe2+ (aq) +0.771 12 (s) + 2e → 21+ (aq) +0.536 Cu2+ + 2e → Cu(s) +0.34 2H+ + 2e → H2 (g) Pb2+ + 2e → Pb (s) -0.126 Ni2+...
help with these please Consider the following half-reactions: Half-reaction Eo (V) F2(g)+ 2e 2F (aq) 2.870V Sn2 (aq) + 2e- Sn(s) 0.140V Cr3 (aq) + 3e° _ Cr(s)-0.740V (1) The strongest oxidizing agent is: enter formula (2) The weakest oxidizing agent is: (3) The weakest reducing agent is: (4) The strongest reducing agent is: (5) Will F2(g) oxidize Cr(s) to Cr3 (aq)? (6) Which species can be oxidized by Sn2 (aq)? If none, leave box blank. Consider the following half-reactions:...
Consider the following half-reactions: Half-reaction E° (V) F2(g) + 2 —> 2F (aq) 2.870V Co2+(aq) + 2e — Co(s) -0.280V A13+(aq) + 3e Al(s) -1.660V . (1) The strongest oxidizing agent is ter (2) The weakest oxidizing agent is: (3) The weakest reducing agent is: (4) The strongest reducing agent is: (5) Will F2(g) oxidize Al(s) to AM+ (aq)? (6) Which species can be reduced by Co(s)? If none, leave box blank.
Question 7 Using the table of standard reduction potentials shown below, calculate the standard cell potential for a battery based on the following reactions. • Pet2 + 2e + Fe . 2 Li + 2 Li + 2e Reduction Half-Reaction F2 +2e + 2F MnO + 8H+ Se + Mn+2+ 4 H 0 Cl2 + 2e + 20 02 + 4H' + 4e + 2 H2O Ag+ e -- Ag Fet) + e + Fe2 O2 + 2 H2O +...
Consider the following half-reactions: Half-reaction F2(g) + 2e - 2H+ (aq) + 2 Mn2+ (aq) + 2e E° (V) 2F (aq) 2.870V H2(g) 0.000V Mn(s) -1.180V The strongest oxidizing agent is: enter formula / / The weakest oxidizing agent is: / The weakest reducing agent is: The strongest reducing agent is: Will Mn2+ (aq) reduce F2(g) to F"(aq)? Which species can be reduced by H2(g)? If none, leave box blank. Consider the following half-reactions: Half-reaction E° (V) Br2(1) + 2e...
12. Using two half reactions that have NEGATIVE standard reduction potentials results results in a battery that... Reduction Half-Reaction F2(g) + 2e →2F(aq) S2082 (aq) + 2e- → 25042 (aq) O2(g) + 4H+ (aq) + 4e → 2H2O(1) Br2(1) + 2e + 2Br (aq) Agt(aq) + e → Ag(s) Fe3+ (aq) + e- → Fe2+ (aq) 126) + 2e → 21 (aq) Cu2+ (aq) + 2e → Cu(s) Sn4+ (aq) + 2e → Sn2+ (aq) S(s) + 2H+ (aq) +...
Question 2 (1 point) Given the following half reactions with their corresponding standard reduction potentials, which of the following is/are true for the overall reaction happening under standard conditions? NO3 + 2H+ + 2e → NO2 + H20 E'O=0.421 V + O2 + 2H+ + 2e H20 E'=0.816 V (CHECK THE ONE(S) THAT IS/ARE CORRECT) 1) AE'' = 0.395 V for the spontaneous reaction. 2) % O2 + NO2 + NO3 is a spontaneous reaction. 3) O2 is the reducing...