Question

1. A reinforced slab built integrally with beam consists of four spans (8 6 on- center). The clear span of the slab is 7 6 I just need help with (I). I can not seem to find the self-weight equation to add to my dead load.
0 0
Add a comment Improve this question Transcribed image text
Answer #1

You simply write the given load data as given separately as

  • Dead load given = 30 psf.
  • Live load given = 160 psf
  • Write the other loads as given = ?..........
  • After that, add all the loads as Live load + Dead load + and so on the other load values like Finishing load, etc.

160+30+...................=

  • Write the Summation of all loads as Total Load = ?.....
  • Then, multiply the Total Load with Factor of safety = 1.5 as,

Factored or design load = Total load x Factor of safety = Total load x 1.5

(This is the easiest way)

Add a comment
Know the answer?
Add Answer to:
I just need help with (I). I can not seem to find the self-weight equation to...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 5:06 0 < HW #7 HW #7-Due 4/10/2019.doc t] .Calculate strain in tension steel and nominal moment s...

    5:06 0 < HW #7 HW #7-Due 4/10/2019.doc t] .Calculate strain in tension steel and nominal moment strength for the precast section shown below. Given:f C." 4,000 psi,f,-60,000 psi (a) A-3.00 i 2 (b) A,-5.641 2 30 in 26 A, in 2. A reinforced slab (3.5 inch thickness) built integrally with beam consists of four spans (8'6" ft. on-center). The clear span of the slab is 7" 6" for all spans including the end span. The service live load on...

  • A rectangular beam having b=16 in and d=26 in spans 28 ft face to face of...

    A rectangular beam having b=16 in and d=26 in spans 28 ft face to face of simple supports. It is reinforced for flexure with 6#11 bars that continue uninterrupted to the ends of the span. It is to carry service dead load 2.0 kips/ft (including self weight) and service live load 3.6 kips/ft, both uniformly distributed along the span. Design the shear reinforcement using vertical U stirrups. Economize the spacing of stirrups in appropriate number of bands. Material strengths are...

  • Problem Two: The beam shown below part is for an interior span and is cast monolithically with a one-way slab. The clear span for the beam is 30 feet, and the clear spacing between beams is 10 fee...

    Problem Two: The beam shown below part is for an interior span and is cast monolithically with a one-way slab. The clear span for the beam is 30 feet, and the clear spacing between beams is 10 feet. (a) Reinforcement is shown for the positive moment region. Determine if the beam is adequate to support a uniformly distributed, factored load of 5 k/ft. (b) Design the slab reinforcement for the positive moment region using a factored load of 500 psf....

  • Name: Date: 2. (+35) Design a typical interior tension-reinforced T-beam to resist positive moment. Beam dimension...

    Name: Date: 2. (+35) Design a typical interior tension-reinforced T-beam to resist positive moment. Beam dimension is given. The service loads are 150 psf dead load (doesn't include the beam weight) and 350 psf live load. The beam is on a simple span of 20 ft. Use f:=4000 psi for strength concrete and fy=60000 psi for steel reinforcement. 8-0* (typ.)

  • Need help with E and F please. 3. The beam shown in the figure below is...

    Need help with E and F please. 3. The beam shown in the figure below is carrying superimposed dead load of 25 kN/m and use and occupancy load of 45 kN/m. For preliminary analysis, assume a self weight of 10 kN/m. We are required to find the maximum positive (tension at the bottom) and negative (tension at the top) moments due to the factored loads, and then design the beam CIV E 374-RC-Lab 3 Fall 2018 (a) Determine the maximum...

  • The T-beam shown in Figure 1 supports the un-factored dead load of 1.4 kips/ft and live...

    The T-beam shown in Figure 1 supports the un-factored dead load of 1.4 kips/ft and live load of 1.5 kips/ft. The dead load does not include the self-weight of the beam. The material properties are as follows: fc’=3000 psi; fy=60,000 psi. Design the shear reinforcement (stirrups). Plot the stirrups distribution along the span of the beam. DL= 1.4 kips/ft ; L2=1.5 kips/Ft * 75 Sz=7 X * b=3616. hr-6in k ) انا امه hw-lain + * bw=12 in

  • A rectangular beam having b-10 in. and d= 17.5 in. spans 15 ft face to face...

    A rectangular beam having b-10 in. and d= 17.5 in. spans 15 ft face to face of simple supports. It is reinforced for flexure with three No. 9 (No. 29) bars that continue uninterrupted to the ends of the span. It is to carry service dead load D 1.27 kips/ft (including self-weight) and service live load L -3.70 kips/ft, both uniformly distributed along the span. Design the shear reinforcement, using No. 3 (No. 10) vertical U stirrups. The more approximate...

  • Design a simple-span, one-way slab to carry a uniformly distributed live load of 375 psf plus...

    Design a simple-span, one-way slab to carry a uniformly distributed live load of 375 psf plus the self-weight of the slab. The span is 10-ft., center-to-center of the supports. Assume fe' = 4,000 psi and fy = 60,000 psi. Design per foot of width. Use #5 bars for both longitudinal and temperature and shrinkage reinforcement. (30 pts.)

  • You are given the task of checking the adequacy of a simply supported slab of 10-inch...

    You are given the task of checking the adequacy of a simply supported slab of 10-inch thickness, 12 ft span. The reinforcement used is #7 rebar at 6 inches on center. The distributed live load on the slab is 600 psf respectively. Assume f’c=3,000 psi, fy=60,000 psi. Determine if the slab is structurally sufficient, and post your detail calculations as well.

  • Could you please help me on question 7. Thank you very much. The floor system shown...

    Could you please help me on question 7. Thank you very much. The floor system shown below consists of normalweight concrete (150 pcf). Beams C2 ! LT 1 7.0 inch ! h=20 in G2! 12 in Girders BI 1 7.0 inch Slab 8 ft span h 24 in ----- - -- - --- 15 in 15 ft 15 ft Use 4000 psi concrete and Gr. 60 reinforcing steel. Assume 0.75 inch clear cover. Include concrete self-weight and a superimposed dead...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT